2x^2+2x-10=2(x^2+x-5)

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Solution for 2x^2+2x-10=2(x^2+x-5) equation:


Simplifying
2x2 + 2x + -10 = 2(x2 + x + -5)

Reorder the terms:
-10 + 2x + 2x2 = 2(x2 + x + -5)

Reorder the terms:
-10 + 2x + 2x2 = 2(-5 + x + x2)
-10 + 2x + 2x2 = (-5 * 2 + x * 2 + x2 * 2)
-10 + 2x + 2x2 = (-10 + 2x + 2x2)

Add '10' to each side of the equation.
-10 + 2x + 10 + 2x2 = -10 + 2x + 10 + 2x2

Reorder the terms:
-10 + 10 + 2x + 2x2 = -10 + 2x + 10 + 2x2

Combine like terms: -10 + 10 = 0
0 + 2x + 2x2 = -10 + 2x + 10 + 2x2
2x + 2x2 = -10 + 2x + 10 + 2x2

Reorder the terms:
2x + 2x2 = -10 + 10 + 2x + 2x2

Combine like terms: -10 + 10 = 0
2x + 2x2 = 0 + 2x + 2x2
2x + 2x2 = 2x + 2x2

Add '-2x' to each side of the equation.
2x + -2x + 2x2 = 2x + -2x + 2x2

Combine like terms: 2x + -2x = 0
0 + 2x2 = 2x + -2x + 2x2
2x2 = 2x + -2x + 2x2

Combine like terms: 2x + -2x = 0
2x2 = 0 + 2x2
2x2 = 2x2

Add '-2x2' to each side of the equation.
2x2 + -2x2 = 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
0 = 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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